Machine A, in millilitres
498, 500, 501, 502 has range 502 − 498 = 4 ml.
Before this page: read a list in order and identify its smallest and largest values.
The range is the distance from the smallest value to the largest value. Subtract the smallest value from the largest; write one number with the same unit as the data.
Find the largest and smallest values, then subtract.
The range is 8, not 20 ÷ 5. Dividing the total by the count finds the mean, not the range.
Two machines fill the same bottle several times. A smaller range means the fills stay within a narrower interval, so the machine is more consistent at measuring the same quantity.
498, 500, 501, 502 has range 502 − 498 = 4 ml.
494, 499, 503, 506 has range 506 − 494 = 12 ml.
Machine A has the smaller range, so its fills are more consistent. The range compares consistency here because both lists measure the same quantity in the same unit.
The range uses only the smallest and largest values, so one unusual value changes it immediately.
4, 6, 7, 9 has range 9 − 4 = 5.
Replacing 9 with 30 gives range 30 − 4 = 26.
The range rises from 5 to 26 because the largest value moved away from the other three. The range does not show whether the other values are close together.
The range cannot be negative: the largest value is at least as large as the smallest. It is zero only when every value is the same.
12 ≤ 20, so 20 − 12 = 8 is non-negative. The answer keeps the data's units.